0.003x^2-0.03x-9=0

Solution for 0.003x^2-0.03x-9=0 equation:

0.003x^2-0.03x-9=0

a = 0.003; b = -0.03; c = -9;
Δ = b2-4ac
Δ = -0.032-4·0.003·(-9)
Δ = 0.1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.03)-\sqrt{0.1089}}{2*0.003}=\frac{0.03-\sqrt{0.1089}}{0.006}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.03)+\sqrt{0.1089}}{2*0.003}=\frac{0.03+\sqrt{0.1089}}{0.006}
$